数据库环境：SQL SERVER 2005
现有一个表的数据如下，id是主键，p1，p2是字符串类型，如果当前行的p1，p2字段的值分别等于其它行
的字段p2，p1的值，则视这2行记录为一组。比如，id=1和id=5就属于同一组数据。同一组数据只显示id最小
的那行记录，没有组的数据全部显示。
实现思路：
将表进行自关联左联，假设表的别名是a，b，根据id进行关联，对关联后的结果集进行过滤。如果b.id是空的，则保留，
如果b.id不为空，则只保留a.id比b.id小的记录。
实现的SQL脚本：
/*1.数据准备*/WITH x0 AS ( SELECT 1 AS id , 'A' AS p1 , 'B' AS p2 /*UNION ALL SELECT 0 AS id , 'A' AS p1 , 'B' AS p2*/ UNION ALL SELECT 2 AS id , 'C' AS p1 , 'D' AS p2 UNION ALL SELECT 3 AS id , 'E' AS p1 , 'F' AS p2 UNION ALL SELECT 4 AS id , 'D' AS p1 , 'C' AS p2 UNION ALL SELECT 5 AS id , 'B' AS p1 , 'A' AS p2 UNION ALL SELECT 6 AS id , 'H' AS p1 , 'J' AS p2 UNION ALL SELECT 7 AS id , 'T' AS p1 , 'U' AS p2 UNION ALL SELECT 8 AS id , 'J' AS p1 , 'H' AS p2 /*UNION ALL SELECT 9 AS id , 'I' AS p1 , 'L' AS p2 UNION ALL SELECT 10 AS id , 'J' AS p1 , 'K' AS p2*/ ),/*2.去重*/ x1 AS ( SELECT id , p1 , p2 FROM ( SELECT id , p1 , p2 , ROW_NUMBER() OVER ( PARTITION BY p1, p2 ORDER BY id ) AS rn FROM x0 ) t WHERE rn = 1 ) /*3.求值*/ SELECT a.id , a.p1 , a.p2 FROM x1 a LEFT JOIN x1 b ON b.p1 = a.p2 AND b.p2 = a.p1 WHERE b.id IS NULL OR a.id < b.id
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最终实现的效果如图：
也有网友提出通过ASCII来实现，他的实现SQL脚本如下：
WITH c1 AS ( SELECT 1 AS id , 'A' AS p1 , 'B' AS p2 /*UNION ALL SELECT 0 AS id , 'A' AS p1 , 'B' AS p2*/ UNION ALL SELECT 2 AS id , 'C' AS p1 , 'D' AS p2 UNION ALL SELECT 3 AS id , 'E' AS p1 , 'F' AS p2 UNION ALL SELECT 4 AS id , 'D' AS p1 , 'C' AS p2 UNION ALL SELECT 5 AS id , 'B' AS p1 , 'A' AS p2 UNION ALL SELECT 6 AS id , 'H' AS p1 , 'J' AS p2 UNION ALL SELECT 7 AS id , 'T' AS p1 , 'U' AS p2 UNION ALL SELECT 8 AS id , 'J' AS p1 , 'H' AS p2 /*UNION ALL SELECT 9 AS id , 'I' AS p1 , 'L' AS p2 UNION ALL SELECT 10 AS id , 'J' AS p1 , 'K' AS p2*/ ), c2 AS ( SELECT MIN(id) AS min_id FROM c1 GROUP BY ASCII(p1) + ASCII(p2) ) SELECT c1.* FROM c1 JOIN c2 ON id = min_id
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咋一看，似乎也可以实现同样的需求。实际上，这种写法存在2个问题：
1.如果p1,p2是多个字符，ASCII的方式只会取第一个字符的ASCII
2.ASCII('A')+ASCII('D')=ASCII('B')+ASCII('C'),对于这样的数据，用ASCII的方式无法区分
(本文完)
原标题：自关联去掉组内重复数据
关键词：
我知道了 