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【JAVA并发编程实战】9、锁分段

发布时间:2016-11-18 12:00:10
package cn.study.concurrency.ch11;/** * 锁分段 * @author xiaof * */public class StripedMap { //同步策略:就是对数组进行分段上锁,n个节点用n%LOCKS锁保护 private stati ...
package cn.study.concurrency.ch11;/** * 锁分段 * @author xiaof * */public class StripedMap {  //同步策略:就是对数组进行分段上锁,n个节点用n%LOCKS锁保护  private static final int N_LOCKS = 16;  private final Node[] buckets;  private final Object[] locks;    private static class Node  {    private String name;    private Node next;    private String key;    private String value;    public String getValue() {      return value;    }    public void setValue(String value) {      this.value = value;    }    public String getName() {      return name;    }    public void setName(String name) {      this.name = name;    }    public Node getNext() {      return next;    }    public void setNext(Node next) {      this.next = next;    }    public String getKey() {      return key;    }    public void setKey(String key) {      this.key = key;    }      }    public StripedMap(int numBuckets)  {    buckets = new Node[numBuckets];    //创建对应hash的锁    locks = new Object[N_LOCKS];    for(int i = 0; i < N_LOCKS; ++ i)    {      locks[i] = new Object();    }  }    private final int hash(Object key)  {    //取绝对值    return Math.abs(key.hashCode() % buckets.length);  }    //get和clear  public Object get(Object key)  {    int hash = hash(key);    synchronized(locks[hash % N_LOCKS])    {      //分段上锁      for(Node m = buckets[hash]; m != null; m = m.next)      {        if(m.key.equals(key))          return m.value;      }    }        return null;  }    /**   * 清除所有的数据,但是没有要求说要同时获取全部的锁的话,可以进行这样的释放操作   */  public void clear()  {    for(int i = 0; i < buckets.length; ++i)    {      synchronized(locks[i % N_LOCKS])      {        buckets[i] = null;      }    }  }}

原标题:【JAVA并发编程实战】9、锁分段

关键词:JAVA

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