一般做OA类管理系统,经常涉及到“组织架构”的概念,那么像这种有上下层级关系的数据一般会做成树形菜单的方式显示,底层代码必定会用到递归算法。这篇随笔的目的就是要谈谈除了用树形菜单来显示这种上下层级关系的数据,还有其他的显示方式吗?答案是有的 ...
一般做OA类管理系统,经常涉及到“组织架构”的概念,那么像这种有上下层级关系的数据一般会做成树形菜单的方式显示,底层代码必定会用到递归算法。这篇随笔的目的就是要谈谈除了用树形菜单来显示这种上下层级关系的数据,还有其他的显示方式吗?答案是有的,例如即将要谈到的二维表显示方式,同时也是本随笔的核心内容。
首先来看二维表的显示效果图:
如果看到这里,你觉得这就是你想要的显示效果,或者对此比较感兴趣。请接着往下看的实现步骤:
1.取出所有的数据临时保存到DataTable中,即内存中,拼html时直接查DataTable中的数据,不用去反复读取数据库,提高效率;
2.根据节点编号获取该节点下所有的末端子节点编号,因为末端子节点的个数就决定了<table>的行数;
3.将查到的末端子节点编号的所有父节点编号也查出来,拼接起来,就知道了<table>的每行的列数;
4.对节点的编号进行排序,这样可以把每列下的相同行的节点编号集中在一起,方便后面的合并单元格;
5.遍历行和列,合并每列相同行的单元格;
6.最后一步,拼接空白的列。
如下是具体代码实现过程:
1 using System; 2 using System.Collections.Generic; 3 using System.Linq; 4 using System.Web; 5 using System.Data; 6 using System.Text; 7 8 /// <summary> 9 ///KpiTable 的摘要说明 10 /// </summary> 11 public class KpiTable 12 { 13 DBUtility.SQLHelper sqlhelper = new DBUtility.SQLHelper(); 14 public get='_blank'>string GetKpiTable(string kpino, string businessno, string tenderno) 15 { 16 //1.取出所有的数据临时保存到dt2,即内存中,拼html时直接查dt2中的数据,不用去反复读取数据库,提高效率 17 DataTable dt2 = new DataTable(); 18 { 19 DataSet ds = new DataSet(); 20 int i = sqlhelper.RunSQL(string.Format("select count(1) from sys.objects where name = 'KpiValue{0}'", businessno)); 21 if (string.IsNullOrEmpty(tenderno) || i<1)//如果有标段编号就要把KpiValueXXX表里的KpiValue1查出来显示 22 { 23 sqlhelper.RunSQL(string.Format(@"select KpiNo,KpiName,KpiInfo,ISNULL(KpiParentNo,0) KpiParentNo,KpiWeight,0 KpiValue1,'' KpiMethod,'' KpiSampleType,'' KpiRule,'' KpiCriterion,'' KpiAreaRule,'' KpiSampleRule from KpiTree{0} 24 union all select KpiNo,KpiName,KpiInfo,ISNULL(KpiParentNo,0) KpiParentNo,KpiWeight,0 KpiValue1,KpiMethod,KpiSampleType,KpiRule,KpiCriterion,KpiAreaRule,KpiSampleRule from Kpi{0}",businessno), ref ds); 25 } 26 else 27 { 28 sqlhelper.RunSQL(string.Format(@"select * from ( 29 select KpiNo,KpiName,KpiInfo,ISNULL(KpiParentNo,0) KpiParentNo,KpiWeight,0 KpiValue1,'' KpiMethod,'' KpiSampleType,'' KpiRule,'' KpiCriterion,'' KpiAreaRule,'' KpiSampleRule from KpiTree{0} 30 union all select KpiNo,KpiName,KpiInfo,ISNULL(KpiParentNo,0) KpiParentNo,KpiWeight,0 KpiValue1,KpiMethod,KpiSampleType,KpiRule,KpiCriterion,KpiAreaRule,KpiSampleRule from Kpi{0} 31 ) a left join KpiValue{0} b on a.kpino = b.kpino and TenderNo='{1}'", businessno, tenderno), ref ds); 32 } 33 dt2 = ds.Tables[0]; 34 } 35 //2.根据节点编号获取该节点下所有的末端子节点编号,因为末端子节点的个数就决定了table的行数 36 DataTable dt = new DataTable(); 37 { 38 DataSet ds = new DataSet(); 39 if (string.IsNullOrEmpty(kpino) || kpino == "0") 40 { 41 sqlhelper.RunSQL(string.Format(@"select kpino from (select kpino from kpitree{0} union all select kpino from Kpi{0}) t where kpino not in (select isnull(KpiParentNo,0) from (select KpiParentNo from kpitree{0} union all select KpiParentNo from Kpi{0}) t)", businessno), ref ds); 42 } 43 else 44 { 45 string endKpiNo = RecursionEndKpiNo(dt2, kpino).Trim(','); 46 endKpiNo = endKpiNo == "" ? "0" : endKpiNo; 47 string kpinos = string.Empty; 48 foreach (string str in endKpiNo.Split(',')) { kpinos += "'" + str + "',"; } 49 kpinos = kpinos.Trim(','); 50 sqlhelper.RunSQL(string.Format(@"select kpino from (select kpino from kpitree{0} union all select kpino from Kpi{0}) t where kpino not in (select isnull(KpiParentNo,0) from (select KpiParentNo from kpitree{0} union all select KpiParentNo from Kpi{0}) t) and kpino in ({1})", businessno, kpinos), ref ds); 51 } 52 dt = ds.Tables[0]; 53 } 54 //3.将查到的末端子节点编号的所有父节点编号也查出来,拼接起来,就知道了table的每行的列数 55 foreach (DataRow row in dt.Rows) 56 { 57 row["kpino"] = Recursion(dt2, row["kpino"]); 58 } 59 //4.对编号进行排序,这样可以把每列下的相同行的节点编号集中在一起,方便后面的合并单元格 60 var drArray = dt.Select("1=1", "kpino"); 61 //5.限制输出kpino之前的父节点信息 62 foreach (DataRow row in drArray) 63 { 64 int index = row["kpino"].ToString().IndexOf(kpino); 65 if (index > -1) 66 { 67 row["kpino"] = row["kpino"].ToString().Substring(index); 68 } 69 } 70 //6.遍历行和列 71 int maxCount = GetMaxCount(drArray); 72 StringBuilder sbJson = new StringBuilder(); 73 for (int i = 0; i < drArray.Length; i++) 74 { 75 DataRow row = drArray[i]; 76 sbJson.Append("<tr>"); 77 var kpinoArray = row["kpino"].ToString().Trim(',').Split(','); 78 int kpinoArrayLenth = kpinoArray.Length; 79 for (int j = 0; j < kpinoArrayLenth; j++) 80 { 81 string str = kpinoArray[j]; 82 if (str != "0") 83 { 84 var dr = dt2.Select("kpino='" + str + "'"); 85 //合并每列相同行的单元格 86 if (dr.Length > 0 && !EqualUpColumnValue(i, j, drArray)) 87 { 88 double kpiWeight = GetKpiWeight(dt2, str); 89 double kpiValue = GetKpiValue(dt2, str); 90 string kpiValueStr = string.IsNullOrEmpty(tenderno) ? "" : "[" + (kpiValue * kpiWeight).ToString("0.00") + "]"; 91 string kpiDes = GetKpiDes(dt2, str); 92 sbJson.Append(string.Format("<td rowspan='{0}'>{1}({2}%){3}{4}</td>", GetColspan(i, j, drArray), dr[0]["kpiname"], (kpiWeight * 100).ToString("0.00"), kpiValueStr, kpiDes)); 93 } 94 } 95 } 96 //拼接空白的列 97 for (int j = 0; j < maxCount - kpinoArrayLenth; j++) 98 { 99 sbJson.Append("<td></td>");100 }101 sbJson.Append("</tr>");102 }103 return "<table id='kpitable' border='1px'>" + sbJson.ToString() + "</table>";104 }105 106 private string RecursionEndKpiNo(DataTable dt, object parentId)107 {108 StringBuilder sbJson = new StringBuilder();109 110 DataRow[] rows = dt.Select(string.Format("KpiParentNo = '" + parentId + "'"));111 if (rows.Length > 0)112 {113 foreach (DataRow row in rows)114 {115 string str = RecursionEndKpiNo(dt, row["kpino"]);116 sbJson.Append("" + row["kpino"] + "," + str);117 }118 }119 return sbJson.ToString();120 }121 private bool IsChild(DataTable dt, string parentId)122 {123 DataRow[] rows = dt.Select(string.Format("KpiParentNo = '" + parentId + "'"));124 if (rows.Length > 0)125 {126 return true;127 }128 else129 {130 return false;131 }132 }133 134 private string Recursion(DataTable dt, object parentId)135 {136 StringBuilder sbJson = new StringBuilder();137 138 DataRow[] rows = dt.Select("kpino = '" + parentId + "'");139 if (rows.Length > 0)140 {141 if (rows[0]["KpiParentNo"].ToString() == "0" || rows[0]["KpiParentNo"].ToString() == "")142 {143 sbJson.Append("0,");144 }145 else146 {147 sbJson.Append(Recursion(dt, rows[0]["KpiParentNo"]));148 }149 }150 sbJson.Append(parentId.ToString() + ",");151 return sbJson.ToString();152 }153 private int GetMaxCount(DataRow[] drArray)154 {155 int temp = 0;156 foreach (DataRow row in drArray)157 {158 int count = row["kpino"].ToString().Trim(',').Split(',').Length;159 if (count > temp)160 {161 temp = count;162 }163 }164 return temp;165 }166 private bool EqualUpColumnValue(int rowIndex, int colIndex, DataRow[] drArray)167 {168 if (rowIndex == 0)169 {170 return false;171 }172 173 string[] kpinoArray = drArray[rowIndex - 1]["kpino"].ToString().Trim(',').Split(',');174 if (kpinoArray.Length > colIndex)175 {176 string upColumnValue = drArray[rowIndex]["kpino"].ToString().Trim(',').Split(',')[colIndex];177 if (upColumnValue == kpinoArray[colIndex])178 {179 return true;180 }181 else182 {183 return false;184 }185 }186 else187 {188 return false;189 }190 }191 private int GetColspan(int rowIndex, int colIndex, DataRow[] drArray)192 {193 int colspan = 1;194 string[] kpinoArray = drArray[rowIndex]["kpino"].ToString().Trim(',').Split(',');195 196 while (rowIndex < drArray.Length - 1)197 {198 string[] kpinoArray2 = drArray[rowIndex + 1]["kpino"].ToString().Trim(',').Split(',');199 if (kpinoArray2.Length > colIndex)200 {201 if (kpinoArray[colIndex] == kpinoArray2[colIndex])202 {203 colspan++;204 }205 else206 {207 break;208 }209 }210 else211 {212 break;213 }214 rowIndex++;215 }216 return colspan;217 }218 private double GetKpiWeight(DataTable dt, string kpino)219 {220 double kpiWeight = 0;221 var drArray = dt.Select("kpino='" + kpino + "'");222 if (drArray.Length > 0)223 {224 string kpiParentNo = drArray[0]["KpiParentNo"].ToString();225 double kpino_KpiWeight = Convert.ToDouble(drArray[0]["KpiWeight"]);226 drArray = dt.Select("KpiParentNo='" + kpiParentNo + "'");227 if (drArray.Length > 0)228 {229 double result = 0;230 foreach (DataRow row in drArray)231 {232 result += Convert.ToDouble(row["KpiWeight"]);233 }234 kpiWeight = (kpino_KpiWeight / result);235 }236 }237 return kpiWeight;238 }239 private double GetKpiValue(DataTable dt, string kpino)240 {241 var drArray = dt.Select(string.Format("kpino='{0}'",kpino));242 if (drArray.Length>0)243 {244 return Convert.ToDouble(drArray[0]["KpiValue1"]);245 }246 return 0;247 }248 private string GetKpiDes(DataTable dt, string kpino)249 {250 string des = string.Empty;251 var drArray = dt.Select(string.Format("kpino='{0}'",kpino));252 if (drArray.Length>0)253 {254 string KpiMethod = drArray[0]["KpiMethod"].ToString();255 string KpiSampleType = drArray[0]["KpiSampleType"].ToString();256 string KpiRule = drArray[0]["KpiRule"].ToString();257 string KpiCriterion = drArray[0]["KpiCriterion"].ToString();258 string KpiAreaRule = drArray[0]["KpiAreaRule"].ToString();259 string KpiSampleRule = drArray[0]["KpiSampleRule"].ToString();260 261 //表格样式262 if (!string.IsNullOrEmpty(KpiMethod))263 {264 //des += "<table id='kpitabledes'>";265 //des += "<tr><td>计算方法:</td><td>" + KpiMethod +"</td></tr>";266 //des += "<tr><td>采样类别:</td><td>" + KpiSampleType + "</td></tr>";267 //des += "<tr><td>评价标准:</td><td>" + KpiRule + "</td></tr>";268 //des += "<tr><td>规范要点:</td><td>" + KpiCriterion + "</td></tr>";269 //des += "<tr><td>测区规则:</td><td>" + KpiAreaRule + "</td></tr>";270 //des += "<tr><td>测点规则:</td><td>" + KpiSampleRule + "</td></tr>";271 //des += "</table>";272 }273 274 //换行样式 275 //if (!string.IsNullOrEmpty(KpiMethod)) { des += "<br />计算方法:" + KpiMethod; }276 //if (!string.IsNullOrEmpty(KpiSampleType)) { des += "<br />采样类别:" + KpiSampleType; }277 //if (!string.IsNullOrEmpty(KpiRule)) { des += "<br />评价标准:" + KpiRule; }278 //if (!string.IsNullOrEmpty(KpiCriterion)) { des += "<br />规范要点:" + KpiCriterion; }279 //if (!string.IsNullOrEmpty(KpiAreaRule)) { des += "<br />测区规则:" + KpiAreaRule; }280 //if (!string.IsNullOrEmpty(KpiSampleRule)) { des += "<br />测点规则:" + KpiSampleRule; } 281 }282 return des;283 }284 285 286 287 288 }
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原标题:议:如何将树形菜单形式的数据转化成HTML的二维表(相同内容需合并单元格)
关键词:HTML
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